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12 July, 13:02

Eric explains that all circles are similar using the argument shown.

1. Let there be two circles, Circle A and circle B.

2. There exists a translation that can be performed on circle A such that it will have the same center as circle B.

4. Thus, there exists a sequence of transformations that can be performed on circle A in order to obtain circle B.

5. Therefore, circle A is similar to circle B.

6. Since circle A and circle B can be any circles, all circles are similar

Which statement could be step 3 of the argument?

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  1. 12 July, 13:26
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