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3 July, 10:41

What are the focus and directrix of the parabola with the given equation x=-1/8y^2?

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  1. 3 July, 10:56
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    The parabola y²=4px has vertex (0,0), focus (0, p) and the equation of the diretrix x=-p.

    from our expression:

    x=-1/8y²

    multiply through by - 8 we get:

    -8x=y²

    copmaring to

    y²=4px

    4p=-8

    p-2

    so it has vertex (0,0), focus (p, 0) = (-2,0)

    equation of directrix x=-p, or x=2

    equation of the axis of symmetry y=0
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