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6 July, 04:31

What is the y=mx+b form for 3y+9=x+3

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  1. 6 July, 04:41
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    Y = 1/3x - 2

    To get y by itself you have to subtract 9 and divide 3 so

    3y+9=x+3

    -9 - 9 subtract 9

    3y = X-6

    /3 = / 3 divide 3

    Y = x/3 - 6/3 always imaginary 1 in front of x and you can divide - 6 divided by 3 so its

    Y=1/3x-2
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