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How do you solve

1-cos2x/cosx •cscx=tanx

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  1. 26 May, 00:28
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    (1-cos^2x/cosx) * cosecx

    (sin^2x/cosx) * sinx (where 1-cos^2x=sin^2x) and 1/cscx=sinx

    sinx/cosx=tanx (divide by sinx)

    hence proved
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