A golf ball is chipped into the air from a small hill with an upward velocity of 50 ft/s. Its height h in feet after t seconds is given by the function. What is the maximum height in feet that the ball reaches? Round your answer to the nearest whole number.

equation: - 16t^2+50t+10

Question

Spud

Mathematics

13 December, 05:50

A golf ball is chipped into the air from a small hill with an upward velocity of 50 ft/s. Its height h in feet after t seconds is given by the function. What is the maximum height in feet that the ball reaches? Round your answer to the nearest whole number.

equation: - 16t^2+50t+10

+3

Answers (1)

Know the Answer?

Dalia Hudson · Answer 1

From the model given:

h (t) = - 16t^2+50t+10

at the maximum height h' (t) = 0

from the function:

h' (t) = - 32t+50

thus

-32t+50=0

t=50/32

thus at maximum height:

t=50/32~1.5625

hence, the maximum height will be:

distance=speed*time

distance=1.5625*50

=78.125 ft

A golf ball is chipped into the air from a small hill with an upward velocity of 50 ft/s. Its height h in feet after t seconds is given by the function. What is the maximum height in feet that the ball reaches? Round your answer to the nearest whole number.equation: - 16t^2+50t+10

A golf ball is chipped into the air from a small hill with an upward velocity of 50 ft/s. Its height h in feet after t seconds is given by the function. What is the maximum height in feet that the ball reaches? Round your answer to the nearest whole number.

equation: - 16t^2+50t+10