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Chum
Mathematics
23 December, 03:07
Solve for x
1. log (x+9) = log (2x-7)
2. log (x-1) ^2=log (-5x-1)
+2
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1
)
Jeremiah Whitney
23 December, 03:28
0
Lets first solve the first one:
log (x+9) = log (2x-7)
Convert the logarithmic equation to an exponential equation.
10^ log (x+9) = 10^ log (2x-7)
Remember that 10^ logx = x, so
x+9=2x-7
Move values with 'x' to the right hand side.
7+9=2x-x
Combine like terms.
16=x so,
x=16
Check:
log (x+9) = log (2x-7)
If x=16
log (16+9) = log (2 (16) - 7)
log25 = log (32-7)
log25 = log25
x=16 is a solution.
Solve the second one like i solved this one, try it
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