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27 February, 10:42

If sin Θ = 5/6, what are the values of cos Θ and tan Θ?

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  1. 27 February, 10:49
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    Sin t (theta) = 5/6

    cos t = √ (1 - (5/6) ²) = √ (1-25/36) = √ (11/36) = √11 / 6

    tan t = sin t / cos t = 5 / 6 : √11 / 6 = 5 / 6 · 6 / √ 11 = 5 / √11
  2. 27 February, 11:06
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    sin = opp/hyp, so the lacking side, is the adjacent side. 5²+b²=6² b=√ (6²-5²) = √11≈3.32 Cos = adj / hyp = √11 / 6 (simplifying to) 1.66/3 Tan = opp / adj = 5 / √11
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