Y=*^2+4*-5 what is the axis of symmetry?

x = - 2

Step-by-step explanation:

Given a generic equation,

y = ax² + bx + c

the axis of symmetry is given by (-1/2) (b/a)

In this problem, you're given

y = x² + 4x - 5

y = 1x² + 4x + - 5

y = ax² + bx + c

you're b=4, a=1

so your axis of symmetry is:

x = (-1/2) (b/a)

x = (-1/2) (4/1)

x = - 2

Your axis of symmetry is - 2. You must use the equation - b/2a to find your x (axis of symmetry). Then, to find the vertex, you plug your axis of symmetry answer into the equation in place of the x's and solve. Your answer to this is your y. You now have your x and your y which is your vertex. (x, y)