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7 January, 16:24

A shopkeeper buys two types of tea one at $20 for 10 kg and the other at $23 for 10 kg. He mixes the two types and the mixture is sold at $38 for 10 kg. What will be his percentage profit?

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  1. 7 January, 16:39
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    Let us take the case of first type of tea

    Cost of 10 kg of tea one = $20

    Then

    Cost of 1 kg of tea one = (20/10) dollars

    = 2 dollars

    Now let us take the case of the second kind of tea

    Cost of 10 kg of tea = $23

    Then

    Cost of 1 kg of tea = (23/10) dollars

    = 2.3 dollars

    So

    The mixture of 1 kg of tea one

    and 1 kg of second type of tea will cost = (2.0 + 2.3) dollars

    = 4.3 dollars

    Then the cost of 2kg mixture of tea costs = 4.3 dollars

    So

    The cost of 10 kg mixture will cost = (4.3/2) * 10 dollars

    = 4.3 * 5 dollars

    = 21.5 dollars

    Then

    The amount of profit made by selling 10 kg tea at $38 = (38 - 21.5) dollars

    = 16.5 dollars

    So

    Percentage of profit made = (16.5/21.5) * 100

    = 1650/21.5

    = 76.74 percent

    So the percentage of profit made is 76.74%.
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