Which subtraction expression has the difference 1 + 4i? (-2 + 6i) - (1 - 2i) (-2 + 6i) - (-1 - 2i) (3 + 5i) - (2 - i) (3 + 5i) - (2 + i)

(3 + 5i) - (2 + i)

Step-by-step explanation:

(-2 + 6i) - (1 - 2i)

The real parts - 2-1 = - 3

The imaginary parts 6i--2i = 6i+2i = 8i

(-2 + 6i) - (-1 - 2i)

The real parts - 2 + 1 = - 1

The imaginary parts 6i - -2i = 6i+2i = 8i

(3 + 5i) - (2 - i)

The real parts 3-2 = 1

The imaginary parts = 5i - -i = 5i+i = 6i

(3 + 5i) - (2 + i)

The real parts 3-2 = 1

The imaginary parts 5i - i = 4i

then the next question is going to be c