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9 March, 18:34

Boxes A and B contain some counters

box A contains more counters than box B

box A: 4k counters

Box B: k+9 counters

what is the smallest possible value of K

+4
Answers (2)
  1. 9 March, 18:47
    0
    4

    Step-by-step explanation:

    Box A = 4k

    Box B = k+9

    Box A > Box B

    => 4k > k+9

    Subtracting k to both sides

    => 4k-k > 9

    => 3k > 9

    Dividing both sides by 3

    => k > 3

    So, The smallest possible value of k is 4
  2. 9 March, 19:00
    0
    Step-by-step explanation:

    If we take 4 as k then

    4k = 4 (4) = 16 boxes

    k + 9 = 4 + 9 = 13 boxes
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