Becky wants to fence in a rectangular play area for her dog. If she wants the length of the play area to be 9 feet longer than half its width, what should the dimensions of the play area be? Write the dimensions algebraically

The dimension of the play area written algebraically is y²/2 + 9y

Step-by-step explanation:

Let the be x and the width be y

If the length is to be 9 feet longer than half the width,

hence y/2 + 9 = x

hence dimension of the area = (y/2 + 9) * y = y²/2 + 9y

Answer: lenght = 9ft + W/2

widht = W

Step-by-step explanation:

if we define L as the lenght, and W as the width, we have that:

L = 9ft + W/2

Then the dimensions are the lenght and the width, and with only one of these two variables, we have all the dimensions, that are

lenght = 9ft + W/2

widht = W