The load, p (in pounds), that can be safely supported by a horizontal beam varies jointly as the product of the width, w (in feet), of the beam and the square of the depth, d (in feet), and inversely as its length, l (in feet). if a beam has a width of 2 feet, a depth of 1 foot and a length of 4 feet, the load it can support is 10 pounds. how much could the beam hold if the beam had a length of 6 feet, a depth of 2 feet, and a width of 3 feet?

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22 May, 17:05

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Amaris Hodge · Answer 1

The formula would be

wd^2c/l = p

(2*1^2c) / 4 = 10

(2*1c) / 4 = 10

2c/4 = 10

c = 20

3*2^2*20/6 = p

3*4*20/6 = p

240 pounds