The Bennett family has 2 kids, 2 boys, and 0 girls. Suppose that for each birth, the probability of a boy birth is 1/2, and the probability of a girl birth is also 1/2. What is the fractional probability of having 2 boys and 0 girls, in any order, in a family's first 2 births

Question

Lawson Webster

Mathematics

8 November, 10:24

The Bennett family has 2 kids, 2 boys, and 0 girls. Suppose that for each birth, the probability of a boy birth is 1/2, and the probability of a girl birth is also 1/2. What is the fractional probability of having 2 boys and 0 girls, in any order, in a family's first 2 births

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Answers (2)

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Lamar Burnett · Answer 1

1/4

Step-by-step explanation:

It would be 1/4 because for the first child, the probability of it being a boy is 1/2, and for the second one, it would have 1/2 as well. There are 4 ways the first two children could have been:

1. boy boy - it is 1/4 of the options.

2. boy girl

3. girl boy

4. girl girl

Another way to solve it is by multiplying 1/2 by 1/2.

Karson Donovan · Answer 2

Probability of both being boys - 1/4

Step-by-step explanation:

Ok so 2 boys and each boy has a probability of 1/2 so 1/2 times 1/4