Jude has a deck of playing cards. He is asked to remove one card at random, then a second card. What could Jude do between the events to ensure they are dependent?

He could get a new, complete deck of playing cards.

He could return the first card back to the original deck.

He could put the first card he removed into his pocket.

He could choose to not remove the second card.

Question

Elias Stokes

Mathematics

26 August, 19:24

Jude has a deck of playing cards. He is asked to remove one card at random, then a second card. What could Jude do between the events to ensure they are dependent?

He could get a new, complete deck of playing cards.

He could return the first card back to the original deck.

He could put the first card he removed into his pocket.

He could choose to not remove the second card.

+1

Answers (2)

Know the Answer?

Maximus Curry · Answer 1

He could put the first card he removed into his pocket, this will make it dependent because instead of the total being 52, there are now 51 cards to choose from. this changes the probability of choosing the next random card from 1/52 to 1/51.

Jaycee Chang · Answer 2

He could put the first card in his pocket so that it will affect the amount of cards he has to draw the second time and the probability of the second card in the deck. For example, if there are 5 cards in total and you pick one card and do not replace it, then the second card's probability is 3/4, since they are only a total of 4 cards in the deck now.