Ask Question
11 December, 05:44

A city is growing at the rate of 0.3% annually. If there were 3,278,000 residents in the city in 1992, find how many (to the nearest ten-thousand) are living in that city in 2000. Use y=3,278,000/left (2.7/right) ^{.003t}

+4
Answers (2)
  1. 11 December, 06:01
    0
    Plug in to your calculator, using t=8 (2000-1992=8)

    3278000*[2.7^ (.003*8) ]

    3357079.9

    which rounds to 3,360,000
  2. 11 December, 06:10
    0
    The answer would be 3,360,000
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A city is growing at the rate of 0.3% annually. If there were 3,278,000 residents in the city in 1992, find how many (to the nearest ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers