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Which sum or difference identity could be used to prove that sin (pie + q) = - sin q

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  1. 7 May, 16:03
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    see below

    Step-by-step explanation:

    sin (a+b) = sin (a) cos (b) + cos (a) sin (b)

    sin (π+q) = sin (π) cos (q) + cos (π) sin (q)

    sin (π) = 0

    cos (π) = - 1

    therefore

    sin (π+q) = 0*cos (q) - sin (q) = - sin (q)
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