A cylinder has a volume of 432 cubic meters. What is the volume of a cylinder with dimensions one-third of the original?

Cylindervolume=hpir^2

V=432

432=hpir^2=original

if each is divided by 3 then

h turns to (1/3) h

r turns to (1/3) r

input and find the effect

(1/3) hpi[ (1/3) r]^2

(1/3) hpi (1/9) r^2

move 1/9 to front

(1/27) hpir^2

compared to original volume (which was hpir^2)

so therefor we multiply the original volume by 1/27

432*1/27=16

the new volume is 16 cubic meters

Finally with knew knowledge i have found a more correct answer*

so in order to find out 1/3 of our dimentions

(since we size 1/3 on our height and radius)

all we have to do is divide by 27

423 : 27 = 16

our correct answer is 27 cubic meters³

:P