A retail shop accepts only cash or checks suppose that 45% of its customers carry cash 44% carry checks and 31% carry both cash and checks what is the probability that a randomly chosen customer at the top of the shop is carrying cash or checks are both

Step-by-step explanation:

The number of customers carrying cash=45% = 0.45

The number of customers carrying checks = 44% = 0.44

The number of customers carrying both = 31% = 0.31

So,

To find the probability we will write the expression:

cash+checks-cash or checks (both) = cash and checks

0.45+0.44-both=0.31

0.45+0.44-0.31=both

0.58=both ...