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Buttercup
Mathematics
5 February, 05:31
Factorize 8x3 - y3-12x2y+6xy2
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Cohen Bailey
5 February, 05:35
0
(2x - y) ^3.
Step-by-step explanation:
8x^3 - y^3 - 12x^2y + 6xy^2
Looks like this is a perfect cube with first term = cube root of 8x^3 and the last term = cube root of - y^3. That is (2x - y) ^3.
Let's expand it:
(2x - y) ^3
= (2x - y) (2x - y) ^2
= (2x - y) (4x^2 - 4xy + y^2)
= 8x^3 - 8x^2y + 2xy^2 - 4x^2y + 4xy^2 - y^3
= 8x^3 - 12x^2y + 6xy^2 - y^3 which is the given expression.
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