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7 June, 02:21

If tan theta + cot theta = 7 then sin theta + cos theta = ?

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  1. 7 June, 02:32
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    √ (9/7)

    Step-by-step explanation:

    tan θ + cot θ = 7

    Write tan and cot in terms of sin and cos.

    (sin θ / cos θ) + (cos θ / sin θ) = 7

    Multiply both sides by sin θ cos θ

    sin² θ + cos² θ = 7 sin θ cos θ

    Use Pythagorean identity.

    1 = 7 sin θ cos θ

    1/7 = sin θ cos θ

    Remember that, we'll use it later. Go back to this step:

    sin² θ + cos² θ = 7 sin θ cos θ

    This time, add 2 sin θ cos θ to both sides.

    sin² θ + 2 sin θ cos θ + cos² θ = 9 sin θ cos θ

    Factor.

    (sin θ + cos θ) ² = 9 sin θ cos θ

    Substitute.

    (sin θ + cos θ) ² = 9 / 7

    Take square root.

    sin θ + cos θ = √ (9/7)

    Option: rationalize the denominator.

    sin θ + cos θ = 3√7 / 7
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