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20 June, 20:12

Can you factor 2x^2+3x+12

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  1. 20 June, 20:34
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    2 (x - x1) (x - x2)

    Step-by-step explanation:

    y = 2x^2 + 3x - 12

    Factored form of y:

    y = a (x - x1) (x - x2)

    Find x1 and x2, the 2 real roots of y. Use the improved quadratic formula.

    D = d 2 = b 2 - 4 a c = 9 + 96 = 105 - -> d = ± √ 105 x = - b 2 a ± d 2 a = - 3 4 ± √ 105 4 Therefor, y = 2 (x + 3 4 + √ 105 4) (x + 3 4 - √ 105 4)
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