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Simon Rhodes
Mathematics
20 July, 02:16
F (x) = - x-2, g (x) = x^2, what is (g°f) (-6)
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Imani Norton
20 July, 02:24
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f (x) = - x - 2
g (x) = x^2
(g°f) (-6) = ?
First, we find f (-6)
f (x) = - x - 2
f (-6) = - (-6) - 2
f (-6) = 6 - 2
f (-6) = 4
Since f (-6) = 4,
(g°f) (-6) = g (4)
g (x) = x^2
g (4) = 4^2
g (4) = 16
Therefore, (g°f) (-6) = 16
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