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6 July, 22:25

How to find the product of (3y^2 + 2y + 2) (3y^2 - 4y - 5)

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  1. 6 July, 22:36
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    = 9y^4 - 6y^3 - 17y^2 - 18y - 10

    Step-by-step explanation:

    (3y^2 + 2y + 2) x (3y^2 - 4y - 5)

    9y^4 - 12y^3 - 15y^2 + 6y^3 - 8y^2 - 10y + 6y^2 - 8y - 10

    = 9y^4 - 6y^3 - 17y^2 - 18y - 10
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