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6 July, 23:05

Elimination

{ 2x-4y+z=11

x+2y+3z=9

3y+5z=12

steps to getting the answer

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Answers (1)
  1. 6 July, 23:24
    0
    2x - 4y + 1z = 11 ⇒ 2x - 4y + 1z = 11

    1x + 2y + 3z = 9 ⇒ 1x + 2y + 3z = 9

    3x + 5z = 12 1x - 2y - 2z = 2

    1x - 2y - 2z = 2

    2x - 4y + 1z = 11 - 2x + 2y - 2z = - 3

    1x + 2y + 3z = 9 ⇒ 1x + 2y + 3z = 9 x - 4z = 1

    3x + 5z = 12 ⇒ 3x + 5z = 12 x - 4z + 4z = 1 + 4z

    -2x + 2y - 2z = - 3 x = 1 + 4z

    1 + 4z - 2y - 2z = 2

    1 - 2y + 4z - 2z = 2

    1 - 2y + 2z = 2

    - 1 - 1

    -2y + 2z = 1

    -2y + 2z - 2z = 1 - 2z

    -2y = 1 - 2z

    -2 - 2

    y = - 0.5 + z

    x + 2 (-0.5 + z) - 2z = 2

    x - 1 + z - 2z + 2 = 2

    x - 1 + z = 2

    + 1 + 1

    x + z = 3

    x - x + z = 3 - x

    z = 3 - x
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