A catering business offers two sizes of baked ziti. Its small ziti dish uses 1 cup of sauce

| cups of cheese. Its large

ziti dish uses 2 cups of sauce and 3 cups of cheese. The business has 100 cups of sauce and 400 cups of cheese on hand.

It makes $6 profit on their small dishes and $5 profit on their large dishes. It wants to maximize the profit from selling the

two sizes of ziti. Let x represent the number of small dishes and y represent the number of large dishes.

What are the constraints for the problem?

Question

Nikolai Harper

Mathematics

6 April, 19:18

A catering business offers two sizes of baked ziti. Its small ziti dish uses 1 cup of sauce

| cups of cheese. Its large

ziti dish uses 2 cups of sauce and 3 cups of cheese. The business has 100 cups of sauce and 400 cups of cheese on hand.

It makes $6 profit on their small dishes and $5 profit on their large dishes. It wants to maximize the profit from selling the

two sizes of ziti. Let x represent the number of small dishes and y represent the number of large dishes.

What are the constraints for the problem?

+4

Answers (1)

Know the Answer?

Karlee Stout · Answer 1

x + 2y ≤ 100 and x + 3y ≤ 400

Maximum profit = 6x + 5y.

Step-by-step explanation:

Let there be x number of small dishes and y number of large dishes to maximize the profit.

So, total profit is P = 6x + 5y ... (1)

Now, the small dish uses 1 cup of sauce and 1 cup of cheese and the large dish uses 2 cups of sauce and 3 cups of cheese.

So, as per given conditions,

x + 2y ≤ 100 ... (1) and

x + 3y ≤ 400 ... (2)

Therefore, those are the constraints for the problem. (Answer)