Solve the system, using substitution. Write the solution as an ordered pair (m, n). 2m-3n = 6, m = 3-2n.

2 (3-2n) - 3n=6

6-4n-3n=6

-7n=0

=> n=0

=> m=3-2*0=3-0=3

(m, n) = (3,0)

M=-2n+3; 2m-3n=6

Solve m=-2n+3 for m

Substitute (-2n+3) for m in 2m-3n=6

2m-3n=6

2 (-2n+3) - 3n=6

-7n+6=6 (Simplify)

-7n+6+-6=6+-6 (Add - 6)

-7n=0

-7n / - 7=0 / - 7 (Divide by - 7)

n=0

Substitute (0) for n in m=-2n+3:

m=-2n+3

m = (-2) (0) + 3

m=3 (Simplify)

m=3 and n=0

So it is (3,0)