Item 12 a regular triangular pyramid has a base and lateral faces that are congruent equilateral triangles. it has a lateral surface area of 57 square centimeters. what is the surface area of the regular triangular pyramid?

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25 October, 16:03

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Monique Gonzalez · Answer 1

Let SA = surface area, la=lateral area, b=base, h=height, l=slant height;

b=l

57=3 (1/2b²)

57/3*2=b²

b = √38

SA = 1/2 (√38) ²+57 cm² = 94 cm²