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28 March, 17:07

The potential solutions to the radical equation sq root of a+5=a+3 are a = - 4 and a = - 1.

Which statement is true about these solutions?

The solution a = - 4 is an extraneous solution.

The solution a = - 1 is an extraneous solution.

Both a = - 4 and a = - 1 are true solutions.

Neither a = - 4 nor a = - 1 are true solutions.

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Answers (1)
  1. 28 March, 17:14
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    The answer is neither a=-4 nor a = - 1 are true solutions because if you use a=-1

    and pulg it in the two problems then you will get 4=2

    just like a=-4 you will get 1=-1

    so your answer should be D.
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