A rectangular lot whose perimeter is 290 ft290 ft is fenced along three sides. an expensive fencing along the lot's length cost $ 36$36 per foot. an inexpensive fencing along the two side widths costs only $ 6$6 per foot. the total cost of the fencing along the three sides comes to $ 4260$4260. what are the lot's dimensions

Question

Sox

Mathematics

28 March, 08:20

A rectangular lot whose perimeter is 290 ft290 ft is fenced along three sides. an expensive fencing along the lot's length cost $ 36$36 per foot. an inexpensive fencing along the two side widths costs only $ 6$6 per foot. the total cost of the fencing along the three sides comes to $ 4260$4260. what are the lot's dimensions

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Bryanna Paul · Answer 1

Let the length be x, the width will be (95-x)

the total cost for the lengths will be:

36*x*2=$72x

Total for width will be:

2*6 * (95-x) = 1140-12x

total amount will be:

72x+1140-12x=4260

solving for x we get:

60x=4260-1140

60x=3120

x=52 ft

thus length=52ft

width=95-52=43 ft