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4 December, 07:37

Use substitution to write an equivalent quadiatic equation

(3x^2) ^2+7 (3x + 2) - 8=0

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  1. 4 December, 07:42
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    9x^4+21x+6=0

    Step-by-step explanation:

    (3x^2) ^2+7 (3x + 2) - 8=0

    ((3^2) * (x^2) ^2) + (7*3x) + (7*2) - 8=0

    9 (x^4) + 21x+14-8=0

    9x^4+21x+6=0
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