4X² + 3x² - 6x + 8

Part A: State if (x+3) is a factor of the polynomial

Part B: What is the if the remainder polynomial

if divided by (x+3)

Question

Davidson

Mathematics

1 January, 05:20

4X² + 3x² - 6x + 8

Part A: State if (x+3) is a factor of the polynomial

Part B: What is the if the remainder polynomial

if divided by (x+3)

+4

Answers (1)

Know the Answer?

Cynthia Tucker · Answer 1

Below.

Step-by-step explanation:

4X² + 3x² - 6x + 8

Part A.

If x+3 is a factor then f (-3) = 0.

f (-3) = 4 (-3) ^3 + 3 (-3) ^2 - 6 (-3) + 8

= - 108 + 27 + 18 + 8

= - 55

So x+3 is NOT a factor.

Part B.

We worked this out in Part A:

-55.

4X² + 3x² - 6x + 8Part A: State if (x+3) is a factor of the polynomialPart B: What is the if the remainder polynomialif divided by (x+3)

4X² + 3x² - 6x + 8

Part A: State if (x+3) is a factor of the polynomial

Part B: What is the if the remainder polynomial

if divided by (x+3)