What are the solutions of the systems? Use any method.

y=x^2-3x+3 y=2x-3

Y = x² - 3x + 3

y = 2x - 3

x² - 3x + 3 = 2x - 3

- 2x - 2x

x² - 5x + 3 = - 3

+ 3 + 3

x² - 5x + 6 = 0

x = - (-5) + / - √ ((-5) - 4 (1) (6))

2 (1)

x = 5 + / - √ (25 - 24)

2

x = 5 + / - √ (1)

2

x = 5 + / - 1

2

x = 5 + 1 x = 5 - 1

2 2

x = 6 x = 4

2 2

x = 3 x = 2

y = x² - 3x + 3

y = (3) ² - 3 (3) + 3

y = 9 - 9 + 3

y = 0 + 3

y = 3

(x, y) = (3, 3)

or

y = x² - 3x + 3

y = (2) ² - 3 (2) + 3

y = 4 - 6 + 3

y = - 2 + 3

y = - 1

(x, y) = (2, - 1)

There can be two solutions.