A bag contains 2 blue, 4 green, and 3 white chips. What is the probability of drawing a white chip then another white chip without replacement?

A.) 7/9

B.) 8/81

C.) 2/3

D.) 1/12

Question

Eliza Hammond

Mathematics

14 August, 18:09

A bag contains 2 blue, 4 green, and 3 white chips. What is the probability of drawing a white chip then another white chip without replacement?

A.) 7/9

B.) 8/81

C.) 2/3

D.) 1/12

+1

Answers (1)

Know the Answer?

Cameron Norris · Answer 1

Total number of chips: 2 + 4 + 3 = 9

total white chips = 3

probability of picking white first = 3/9 = 1/3

after taking one chip there would be 9-1 = 8 chips left

and 3-1 2 white chips left

probability of picking 2nd white chip = 2/8 = 1/4

probability of picking both = 1/3 x 1/4 = 1/12

answer is D

A bag contains 2 blue, 4 green, and 3 white chips. What is the probability of drawing a white chip then another white chip without replacement?A.) 7/9B.) 8/81C.) 2/3D.) 1/12

A bag contains 2 blue, 4 green, and 3 white chips. What is the probability of drawing a white chip then another white chip without replacement?

A.) 7/9

B.) 8/81

C.) 2/3

D.) 1/12