Ask Question
28 January, 12:08

An aircraft carrier left Port 35 traveling north five hours before a container ship. The container ship traveled in the opposite direction going 8 km/h faster than the aircraft carrier for seven hours after which time the ships were 303 km apart. What was the aircraft carrier's speed?

+1
Answers (1)
  1. 28 January, 12:32
    0
    Aircraft carrier speed = 4.97 km/h

    Step-by-step explanation:

    Given that the time taken by the aircraft = 5 hours

    Let the distance covered = X

    Speed = V

    Time taken by the ship = 7 hours

    Let the distance covered = Y

    Speed = 8V

    Since it is 8 km/h faster than the aircraft carrier.

    Using the speed formula

    Speed = distance/time

    Distance = speed * time

    For the aircraft;

    X = 5V

    For the ship:

    Y = 7 * 8V = 56V

    Since they are 303km distance apart,

    X + Y = 303

    5V + 56V = 303

    61V = 303

    V = 303/61

    V = 4.97 km/h

    Aircraft carrier speed = 4.97 km/h
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “An aircraft carrier left Port 35 traveling north five hours before a container ship. The container ship traveled in the opposite direction ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers