The equation for a circle with center (h, k) is (x - h) ^2 + (y - k) ^2 = r^2. If a circle is modeled by the equation x^2 + (y + 6) ^2 = 100, what is the center of the circle?

Question

Jaylan Mccarthy

Mathematics

22 January, 16:55

The equation for a circle with center (h, k) is (x - h) ^2 + (y - k) ^2 = r^2. If a circle is modeled by the equation x^2 + (y + 6) ^2 = 100, what is the center of the circle?

+2

Answers (1)

Know the Answer?

Asia Blackburn · Answer 1

(x - h) ^2 + (y - k) ^2 = r^2

x^2 + (y + 6) ^2 = 100

we can rewrite this as

(x-0) ^2 + (y - - 6) ^2 = 10^2

the center is (0,-6) and the radius is 10