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Kellen Hester
Mathematics
6 January, 01:35
What is t (cos (t)) = 0?
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Amina
6 January, 01:59
0
In radians:
To get 0, only one part of the multiplication needs to be zero for the whole thing to be zero. Thus we get 2 equations:
t=0, and cos (t) = 0
for the first equation, it's pretty self-explanatory and sp we get 0 as one solution.
For the second equation, cos (pi/2) and cos (3pi/2) both equal 0 so both pi/2 and 3pi/2 are answers. Since there is no bound to this problem, the actual answer is:
(2Z+1) pi/2 and 0
(2Z+1) means all odd integers
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