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7 March, 10:37

What is the LCM of x^2+5 and x^2+10x+25?

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  1. 7 March, 10:57
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    (x+5) ² (x²+5)

    Step-by-step explanation:

    Given two functions x²+5 and x²+10x+25, to get their Lowest common factor, we need to to first factorize x²+10x+25

    On factorising we have:

    x²+5x+5x+25

    = x (x+5) + 5 (x+5

    = (x+5) (x+5)

    = (x+5) ²

    The LCM can be calculated as thus

    | x²+5, (x+5) ²

    x+5| x²+5, (x+5)

    x+5| x²+5, 1

    x²+5| 1, 1

    The factors of both equation are x+5 * x+5 * x²+5

    The LCM will be the product of the three functions i. e

    (x+5) ² (x²+5)

    This hives the required expression.
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