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Ariella Serrano
Mathematics
7 March, 10:37
What is the LCM of x^2+5 and x^2+10x+25?
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Tyrell
7 March, 10:57
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(x+5) ² (x²+5)
Step-by-step explanation:
Given two functions x²+5 and x²+10x+25, to get their Lowest common factor, we need to to first factorize x²+10x+25
On factorising we have:
x²+5x+5x+25
= x (x+5) + 5 (x+5
= (x+5) (x+5)
= (x+5) ²
The LCM can be calculated as thus
| x²+5, (x+5) ²
x+5| x²+5, (x+5)
x+5| x²+5, 1
x²+5| 1, 1
The factors of both equation are x+5 * x+5 * x²+5
The LCM will be the product of the three functions i. e
(x+5) ² (x²+5)
This hives the required expression.
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