Find the intercepts of the following equation y=x^2+x-42

Question

Devan Cline

Mathematics

6 January, 18:38

Find the intercepts of the following equation y=x^2+x-42

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Answers (1)

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Kaylee Little · Answer 1

X intercepts are where y=0

0=x^2+1x-42

0 = (x-6) (x+7)

set to zero

x-6=0

x=6

x+7=0

x=-7

x intercepts are (-7,0) and (6,0)

y intercept is where x=0

y=0^2+0-42

y=-42

y intercept is (0,-42)

x intercepts at (-7,0) and (6,0)

y intercept at (0,-42)