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6 January, 18:34

Solve x ym = y x3 for m.

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  1. 6 January, 18:36
    0
    xym-yx3m = 0

    xym (1-1x2) = 0

    xym (1 (un cuadrado) - 1x2) = 0

    xym (1+x) (1-x) = 0

    1+x=0

    1-x=0

    m = 0

    x=-1

    x=1

    Is true

    m=0; x = - 1; 1
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