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Alfred Blackburn
Mathematics
18 April, 14:57
Write as a polynomial:
2 (x-3) (x+3)
+1
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1
)
Wallace
18 April, 15:15
0
Long way:
2 (x-3) (x+3) = 2 (x*x + 3*x - 3*x - 3*3)
2 (x-3) (x+3) = 2 (x^2 - 9)
2 (x-3) (x+3) = 2x^2 - 2*9
2 (x-3) (x+3) = 2x^2 - 18
Shortcut way:
Using formula (x+a) (x-a) = x^2 - a^2, where a = 3, in the case of (x+3) (x-3), so we have
(x+3) (x-3) = x^2 - 9.
Then, we multiply that by 2, which gives 2x^2 - 18.
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