Ask Question
4 September, 04:06

A cylinder's radius is reduced to two-fifths its original size and the height is quadrupled. How has the volume of the cylinder changed?

+4
Answers (1)
  1. 4 September, 04:15
    0
    Let the original volume be pi * r^2 * h where r = radius and h = height.

    The new volume will be pi * (2/5 r) ^2 * 4h = pi*4/25 r^2 4h

    pi*4/25r^2 * 4h / pi r^2 h = 4/25 * 4 = 16/25

    The volume has been reduced by factor of 16/25.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A cylinder's radius is reduced to two-fifths its original size and the height is quadrupled. How has the volume of the cylinder changed? ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers