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9 December, 06:50

A certain law firm consists of 4 senior partners and 6 junior partners. How many different groups of 3 partners can be formed in which at least one member of the group is a senior partner?

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  1. 9 December, 07:08
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    Answer:100

    Step-by-step explanation:

    There are ten total people:

    10C3

    10! / (7!*3!) = 120

    Note: but that includes all the cases where there are no senior partners

    So firstly let figure out the number of cases where there are no senior partners

    because there are 6 junior partners

    6C3

    = 6! / (3!*3!) = 20

    120 - 20 = 100 or the number of possible groups where there is at least 1 senior partner.
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