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14 May, 16:07

Graph the functions below. Arrange the parabolas with respect to the position of their vertices from left to right.

y=F (4x+3)

y=F (x-3)

y=F (2x-1)

y=F (x/2-2

y=F (x-7)

y=F (x+3) / 3

y=F (x-2)

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  1. 14 May, 16:21
    0
    The correct answer for this question is this one:

    If the x position of the vertex for f (x) is k then:

    1. f (k) = > 4x+3=k, x = (k-3) / 4 = (k/4) - (3/4)

    2. x = k+3

    3. x = (k+1) / 2 = (k/2) - (1/2)

    4. x = 2 (k+2) = 2k+4

    5. x = k+7

    6. x = k-3

    7. x = k-2

    So the order depends on the original position of the vertex k, e. g for k=0 the positions would be:

    1. - 3/4

    2. 3

    3. - 1/2

    4. 4

    5. 7

    6. - 3

    7. - 2

    So, therefore, the order would be 6 7 1 3 2 4 5
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