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1 January, 19:00

The lengths of the side of a triangle are 5 cm, 12 cm, and 13 cm. Find the lengths, to the nearest tenth, of the segments into which the bisector of each angle divides the opposite side.

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  1. 1 January, 19:28
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    Side 13 cm the line is divided in the ratio 5:12

    so segment lengths are (5/17) * 13 and (12/17) * 13 = 3.8cm and 9.2

    in similar way side 12 segments would be (5/18) * 12 and (13/18) * 12

    side 5 cm - segments would be (12/25) * 5 and (13/25) * 5
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