2 Marianna is painting a ramp for the school play that is in the shape of a right

triangular prism. The ramp has the dimensions shown. She will not paint the back or

bottom surfaces of the ramp.

Each can of paint covers 1,000 square inches. What is the fewest number of full cans

of paint Marianna will need? Circle the minimum number of cans.

Cans of Paint

50 in, 60 in, 48 in, 14in.

There are 8 cans of paint

Question

Terrence Carpenter

Mathematics

2 August, 03:26

2 Marianna is painting a ramp for the school play that is in the shape of a right

triangular prism. The ramp has the dimensions shown. She will not paint the back or

bottom surfaces of the ramp.

Each can of paint covers 1,000 square inches. What is the fewest number of full cans

of paint Marianna will need? Circle the minimum number of cans.

Cans of Paint

50 in, 60 in, 48 in, 14in.

There are 8 cans of paint

+1

Answers (1)

Know the Answer?

Kailey · Answer 1

4

Step-by-step explanation:

14, 48, and 50 are a Pythagorean triple, so I assume those are the sides of the triangular base. So the length of the prism is 60 inches.

The surface area of the prism, not including the back or bottom, is the sum of the rectangular face and the two triangular bases:

A = Lc + 2 (½ ab)

A = Lc + ab

Plugging in values:

A = (60) (50) + (14) (48)

A = 3672

The surface area is 3672 in². Each bucket of paint covers 1000 in². So Marianna needs 4 buckets of paint.