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11 January, 17:37

A flagpole casts a shadow 10 ft long. if a man 6 ft tall casts a shadow 4ft long at the same time of day, how tall is the flagpole?

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  1. 11 January, 17:48
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    It is like cross multiplication, which is the actually height over the height it casts.

    which is. 6ft. / 4ft. = x / 10ft.

    x is the unknown height the flagpole and 10ft is the height of the shadow.

    You then cross multiple.

    Which will give you

    4ft. x = 10ft. * 6ft.

    which will give you

    4ft. x = 60ft.

    so you switched the place of the 4ft. to the oppose side, it will give you : 4ft.

    It is : because 4ft. has a variable which is x (can also so be any letter, but I used x instead).

    you are now left with

    x = 60ft. : 4ft.

    x = 15ft.

    (15 because 60 : 4 is 15 and ft because you are asked to find how tall the flagpole is in ft.)
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