Ask Question
18 November, 16:59

The mass of two sacks of potatoes is 168 grams. One-eight of the mass of Sack A and three-quarter of the mass of Sack B is 76 grams. Write an equation to find the mass of Sack A.

+5
Answers (1)
  1. 18 November, 17:11
    0
    1/8 (A) + (3/4) (168-A) = 76 is an equation to find the mass of A, the mass of A is 80 grams.

    Step-by-step explanation:

    What do we know?

    Both sacks together are 168 grams. Therefore;

    A+B=168

    One eighth of sack A and three quarters of sack B is equal to 76 grams. Therefore;

    1/8 (A) + (3/4) B=76

    Let's solve using the substitution method to find A. First, we need to isolate and then substitute B for an expression containing A.

    A+B=168

    B=168-A

    Now that we have isolated B, we can substitute '160-A' for B in the other equation.

    1/8 (A) + (3/4) (168-A) = 76

    1/8 (A) - 3/4 (A) + 126=76

    1/8 (A) - 3/4 (A) + 126=-50

    -5/8 (A) = -50

    A=80
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The mass of two sacks of potatoes is 168 grams. One-eight of the mass of Sack A and three-quarter of the mass of Sack B is 76 grams. Write ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers