The circumference of the base of a cylinder is 24π mm. A similar cylinder has a base with circumference of 60π mm. The lateral area of the larger cylinder is 210π mm2.

What is the lateral area of the smaller cylinder?

Given that the figures are similar polygons, the ratio of their ratios should be equal to the square of the ratio of their circumference. If we let x be the lateral area of the smaller cylinder then,

(x/210π) = (24π/60π) ²

The value of x from the equation is,

x = 33.6π

Thus, the area of the smaller cylinder is equal to 33.6π mm².