Attorney A charges a fixed fee on $250 for an initial meeting and $150 per hour for all hours worked after that. Write an equation in slope-intercept form. Attorney B charges $150 for the initial meeting and $175 per hour. Find the charge for 26 hours of work for each attorney. Which is the better deal? At how many hours does this attorney become a better deal?

Question

Jayla Kirby

Mathematics

31 May, 19:25

Attorney A charges a fixed fee on $250 for an initial meeting and $150 per hour for all hours worked after that. Write an equation in slope-intercept form. Attorney B charges $150 for the initial meeting and $175 per hour. Find the charge for 26 hours of work for each attorney. Which is the better deal? At how many hours does this attorney become a better deal?

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Answers (1)

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Jazlynn Chandler · Answer 1

let h be the number of hours then

A → C = 150h + 250 (where C is charge)

B → C = 175h + 150

for 26 hours

A → C = (150 * 26) + 250 = 3900 + 250 = $4150

B → C = (175 * 26) + 150 = 4550 + 150 = $4700

Attorney A is cheaper for 26 hours, thus better deal

Equate the 2 equations to find hours they charge the same

175h + 150 = 150h + 250 (subtract 150h from both sides)

25h + 150 = 250 (subtract 150 from both sides)

25h = 100 (divide both sides by 25)

h = 4 ← number of hours when charges for both are equal

Thus Attorney A becomes a better deal at 5 hours